Solutions Pointers in C | hackerrank solution | Competitive programming question | shaurya coder solution

 

Pointers ! In C

Objective

In this challenge, you will learn to implement the basic functionalities of pointers in C. A pointer in C is a way to share a memory address among different contexts (primarily functions). They are primarily used whenever a function needs to modify the content of a variable that it does not own.

In order to access the memory address of a variable, , prepend it with  sign. For example, &val returns the memory address of .

This memory address is assigned to a pointer and can be shared among various functions. For example,  will assign the memory address of  to pointer . To access the content of the memory to which the pointer points, prepend it with a *. For example, *p will return the value reflected by  and any modification to it will be reflected at the source ().

	void increment(int *v) {
        (*v)++; 
    }
      	int main() {
        int a;
        scanf("%d", &a);
        increment(&a);
        printf("%d", a);
    	return 0;      
    }     

Task

Complete the function void update(int *a,int *b). It receives two integer pointers, int* a and int* b. Set the value of  to their sum, and  to their absolute difference. There is no return value, and no return statement is needed.

• a' = a + b 
• b' = |a - b |

Input Format

The input will contain two integers,  and , separated by a newline.

Output Format

Modify the two values in place and the code stub main() will print their values.

Note: Input/ouput will be automatically handled. You only have to complete the function described in the 'task' section.

Sample Output

4
5

Sample Output

9
1

Explanation

• a' = 4 + 5 = 9
• b' = 4 - 5 = 1   

Solution

#include <stdio.h>

#include <stdlib.h>

void update(int *a,int *b) 

{

    // Pointers in C - Hacker Rank Solution START

    int x,y;

    x = *a + *b;

    y = *a - *b;

    *a = x;

    *b =abs(y); 

    // Pointers in C - Hacker Rank Solution END

}

int main() 

{

    int a, b;

    int *pa = &a, *pb = &b;

    

    scanf("%d %d", &a, &b);

    update(pa, pb);

    printf("%d\n%d", a, b);

    return 0;

}