Basic Data Types Solution | C++ HackerRank - Shaurya Coder

"Basic Data types" With  C++

Problems

Some C++ data types, their format specifiers, and their most common bit widths are as follows:

• Int ("%d"): 32 Bit integer
• Long ("%ld"): 64 bit integer
• Char ("%c"): Character type
• Float ("%f"): 32 bit real value
• Double ("%lf"): 64 bit real value

---

Reading
To read a data type, use the following syntax:

scanf("`format_specifier`", &val)

For example, to read a character followed by a double:

char ch;
double d;
scanf("%c %lf", &ch, &d);

For the moment, we can ignore the spacing between format specifiers.

Printing
To print a data type, use the following syntax:

printf("`format_specifier`", val)

For example, to print a character followed by a double:

char ch = 'd';
double d = 234.432;
printf("%c %lf", ch, d);

Note: You can also use cin and cout instead of scanf and printf; however, if you are taking a million numbers as input and printing a million lines, it is faster to use scanf and printf.

Input Format

Input consists of the following space-separated values: int, long, char, float, and double, respectively.

Output Format

Print each element on a new line in the same order it was received as input. Note that the floating point value should be correct up to 3 decimal places and the double to 9 decimal places.

Sample Input

3 12345678912345 a 334.23 14049.30493

Sample Output

3
12345678912345
a
334.230
14049.304930000

Explanation

Print int 3,
followed by long 12345678912345,
followed by char a,
followed by float 334.23,
followed by double 14049.30493.

Code

#include <iostream>

#include <cstdio>

using namespace std;

int main() 

{

    // Writer Name is Aman Vishwakarma

 int a;

 long long int b;

 char c;

 float d;

 double e;

 scanf("%d %lld %c %f %lf",&a,&b,&c,&d,&e);

 printf("%d\n%lld\n%c\n%f\n%lf",a,b,c,d,e);

return 0;

}